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By A. Henderson (Auth.)

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Finally, one can also use the varying magnetic coupling between two inductors to make a variable inductance (see Chapter 4). Theoretically one can vary an inductance between zero and infinity. 16). The power supplied by the source is p = vi. dv We further have i = C -τ- . If the source strength is made zero after ti seconds, the energy supplied is W=Jpdt=JCv^dt. 0 0 Suppose the voltage is V after ti seconds, then v W= JCvdv = | C V 2 . o (We assume the starting energy to be zero). This energy is stored in the capacitor and is in fact in the electric field.

30 a. Use the node method to calculate the node voltages with respect to earth. b. Give all branch currents in the graph of the network. 33 State whether Ix is larger than, smaller than or equal to Iy. 31 a. Use the node method to solve this network. b. Give all branch currents in the graph of the network. c. Find the power supplied by each of the sources. 32 Use the node method to find the node voltages with respect to earth. 34 a. Use the node method to find the node voltages with respect to earth.

45) The input resistance is the negative of the load. 64. Question: find the current I. With the mesh method we find l=2Ii-I, 0 = -Ii + 8I + 5Ii. 2 A. 64 with Thévenin's theorem. 65). We find l = 2 I i => Ii = | A , Vab = v T = I i - 5 I i = - 2 V . 66). 1 = 2I2 - Is, 0 = -I2 + 2IS + 5I2. It follows that Is = - \ A. 67). Should we calculate Rat>, the intensities of the independent source of 1 V and the dependent current source of 5Ii being set at zero, it follows that RT = x Ω, which is an incorrect result.

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